125/27=(3/5)^2x-1

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Solution for 125/27=(3/5)^2x-1 equation: 



125/27=(3/5)^2x-1

We move all terms to the left:

125/27-((3/5)^2x-1)=0



Domain of the equation: 5)^2x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3/5)^2x-1)+125/27=0

We calculate fractions


()/5^2x-1)*27)+625x/5^2x-1)*27)=0

We calculate fractions

We do not support expression: x^4

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